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(F+1)=2F^2+5F+4
We move all terms to the left:
(F+1)-(2F^2+5F+4)=0
We get rid of parentheses
-2F^2+F-5F+1-4=0
We add all the numbers together, and all the variables
-2F^2-4F-3=0
a = -2; b = -4; c = -3;
Δ = b2-4ac
Δ = -42-4·(-2)·(-3)
Δ = -8
Delta is less than zero, so there is no solution for the equation
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